Equidistant Letters solution codeforces

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Equidistant Letters solution codeforces: You are given a string ss, consisting of lowercase Latin letters. Every letter appears in it no more than twice.
Your task is to rearrange the letters in the string in such a way that for each pair of letters that appear exactly twice, the distance between the letters in the pair is the same. You are not allowed to add or remove letters.
It can be shown that the answer always exists. If there are multiple answers, print any of them.
The first line contains a single integer tt (1≤t≤1031≤t≤103) — the number of testcases.
Each testcase consists of a nonempty string ss, consisting of lowercase Latin letters. Every letter appears in the string no more than twice. The length of the string doesn’t exceed 5252.
For each testcase, print a single string. Every letter should appear in it the same number of times as it appears in string ss. For each pair of letters that appear exactly twice, the distance between the letters in the pair should be the same.
If there are multiple answers, print any of them.
input
3 oelhl abcdcba ac
output
hello ababcdc ac
In the first testcase of the example, the only letter that appears exactly twice is letter ‘l’. You can rearrange the letters arbitrarily, since there are no distances to compare.
In the second testcase of the example, the letters that appear exactly twice are ‘a’, ‘b’ and ‘c’. Initially, letters ‘a’ are distance 66 apart, letters ‘b’ are distance 44 apart and letters ‘c’ are distance 22 apart. They are not the same, so we have to rearrange the letters. After rearrangement, letters ‘a’ are distance 22 apart, letters ‘b’ are distance 22 apart and letters ‘c’ are distance 22 apart. They are all the same, so the answer is valid.
In the third testcase of the example, there are no letters that appear exactly twice. Thus, any rearrangement is valid. Including not changing the string at all.

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