Keep Multiplying Found Values by Two solution leetcode

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You are given an array of integers nums
. You are also given an integer original
which is the first number that needs to be searched for in nums
.
You then do the following steps:
 If
original
is found innums
, multiply it by two (i.e., setoriginal = 2 * original
).  Otherwise, stop the process.
 Repeat this process with the new number as long as you keep finding the number.
Return the final value of original
.
Example 1: Keep Multiplying Found Values by Two solution leetcode
Input: nums = [5,3,6,1,12], original = 3 Output: 24 Explanation:  3 is found in nums. 3 is multiplied by 2 to obtain 6.  6 is found in nums. 6 is multiplied by 2 to obtain 12.  12 is found in nums. 12 is multiplied by 2 to obtain 24.  24 is not found in nums. Thus, 24 is returned.
Keep Multiplying Found Values by Two solution leetcode Example 2:
Input: nums = [2,7,9], original = 4 Output: 4 Explanation:  4 is not found in nums. Thus, 4 is returned.
Constraints: Keep Multiplying Found Values by Two solution leetcode
1 <= nums.length <= 1000
1 <= nums[i], original <= 1000