Maximum Earnings From Taxi solution leetcode
n points on a road you are driving your taxi on. The
n points on the road are labeled from
n in the direction you are going, and you want to drive from point
1 to point
n to make money by picking up passengers. You cannot change the direction of the taxi.
The passengers are represented by a 0-indexed 2D integer array
rides[i] = [starti, endi, tipi] denotes the
ith passenger requesting a ride from point
starti to point
endi who is willing to give a
tipi dollar tip.
For each passenger
i you pick up, you earn
endi - starti + tipi dollars. You may only drive at most one passenger at a time.
rides, return the maximum number of dollars you can earn by picking up the passengers optimally.
Note: You may drop off a passenger and pick up a different passenger at the same point.
Example 1: Maximum Earnings From Taxi solution leetcode
Input: n = 5, rides = [[2,5,4],[1,5,1]] Output: 7 Explanation: We can pick up passenger 0 to earn 5 - 2 + 4 = 7 dollars.
Example 2: Maximum Earnings From Taxi solution leetcode
Input: n = 20, rides = [[1,6,1],[3,10,2],[10,12,3],[11,12,2],[12,15,2],[13,18,1]] Output: 20 Explanation: We will pick up the following passengers: - Drive passenger 1 from point 3 to point 10 for a profit of 10 - 3 + 2 = 9 dollars. - Drive passenger 2 from point 10 to point 12 for a profit of 12 - 10 + 3 = 5 dollars. - Drive passenger 5 from point 13 to point 18 for a profit of 18 - 13 + 1 = 6 dollars. We earn 9 + 5 + 6 = 20 dollars in total.
Constraints: Maximum Earnings From Taxi solution leetcode
1 <= n <= 105
1 <= rides.length <= 3 * 104
rides[i].length == 3
1 <= starti < endi <= n
1 <= tipi <= 105