Maximum Factors Problem solution codechef
You are given an integer NN. Let KK be a divisor of NN of your choice such that K>1K>1, and let M=NKM=NK. You need to find the smallest KK such that MM has as many divisors as possible.
Note: UU is a divisor of VV if VV is divisible by UU.
Input Format
- The first line of the input contains an integer TT – the number of test cases. The test cases then follow.
- The only line of each test case contains an integer NN.
Output Format
For each test case, output in a single line minimum value of KK such that MM has as many divisors as possible.
Constraints
- 1≤T≤30001≤T≤3000
- 2≤N≤1092≤N≤109
Sample Input 1
3
3
4
6
Sample Output 1
3
2
2
Explanation
- Test case 11: The only possible value for KK is 33, and that is the answer.
- Test case 22: There are two cases:
- K=2K=2. Then M=42=2M=42=2, which has 22 divisors (11 and 22).
- K=4K=4. Then M=44=1M=44=1, which has 11 divisor (11).
Therefore the answer is 22.
- Test case 33: There are three cases:
- K=2K=2. Then M=62=3M=62=3, which has 22 divisors (11 and 33).
- K=3K=3. Then M=63=2M=63=2, which has 22 divisors (11 and 22).
- K=6K=6. Then M=66=1M=66=1, which has 11 divisor (11).
Therefore the answer is 22.