Minimum Operations to Make the Array Alternating solution leetcode- You are given a 0-indexed array nums consisting of n positive integers. The array nums is called alternating if: nums[i – 2] == nums[i], where 2 <= i <= n - 1. nums[i - 1] != nums[i], where 1 <= i <= n - 1. In one operation, you can choose an index i and change nums[i] into any positive integer. Return the minimum number of operations required to make the array alternating.

Minimum Operations to Make the Array Alternating solution leetcode

 

Minimum Operations to Make the Array Alternating solution leetcode:- You are given a 0-indexed array nums consisting of n positive integers.

The array nums is called alternating if:

  • nums[i - 2] == nums[i], where 2 <= i <= n - 1.
  • nums[i - 1] != nums[i], where 1 <= i <= n - 1.

In one operation, you can choose an index i and change nums[i] into any positive integer.

Return the minimum number of operations required to make the array alternating.

 

Example 1: Minimum Operations to Make the Array Alternating solution leetcode

Input: nums = [3,1,3,2,4,3]
Output: 3
Explanation:
One way to make the array alternating is by converting it to [3,1,3,1,3,1].
The number of operations required in this case is 3.
It can be proven that it is not possible to make the array alternating in less than 3 operations. 

Example 2: Minimum Operations to Make the Array Alternating solution leetcode

Input: nums = [1,2,2,2,2]
Output: 2
Explanation:
One way to make the array alternating is by converting it to [1,2,1,2,1].
The number of operations required in this case is 2.
Note that the array cannot be converted to [2,2,2,2,2] because in this case nums[0] == nums[1] which violates the conditions of an alternating array.

 

Minimum Operations to Make the Array Alternating solution leetcode Constraints: 

  • 1 <= nums.length <= 105
  • 1 <= nums[i] <= 105

  • SOLUTION:- CLICK HERE

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